Base | Representation |
---|---|
bin | 101111000101101001… |
… | …0011011000010000011 |
3 | 100200000022012122020202 |
4 | 1132023102123002003 |
5 | 3124044001011042 |
6 | 114242052155415 |
7 | 10206606153131 |
oct | 1361322330203 |
9 | 320008178222 |
10 | 101121110147 |
11 | 39981259812 |
12 | 17721308b6b |
13 | 96c6b71c25 |
14 | 4c73cd6751 |
15 | 296c890632 |
hex | 178b49b083 |
101121110147 has 2 divisors, whose sum is σ = 101121110148. Its totient is φ = 101121110146.
The previous prime is 101121110071. The next prime is 101121110171. The reversal of 101121110147 is 741011121101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101121110147 - 28 = 101121109891 is a prime.
It is not a weakly prime, because it can be changed into another prime (101121110177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560555073 + 50560555074.
It is an arithmetic number, because the mean of its divisors is an integer number (50560555074).
Almost surely, 2101121110147 is an apocalyptic number.
101121110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101121110147 is an equidigital number, since it uses as much as digits as its factorization.
101121110147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 101121110147 its reverse (741011121101), we get a palindrome (842132231248).
The spelling of 101121110147 in words is "one hundred one billion, one hundred twenty-one million, one hundred ten thousand, one hundred forty-seven".
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