Base | Representation |
---|---|
bin | 1001001100100110100011… |
… | …0101111111110011011111 |
3 | 1022210201010110201221211221 |
4 | 2103021220311333303133 |
5 | 2311134101133001343 |
6 | 33301235022154211 |
7 | 2062401363541642 |
oct | 223115065776337 |
9 | 38721113657757 |
10 | 10112112000223 |
11 | 3249582669162 |
12 | 1173965a22967 |
13 | 5847500853ac |
14 | 26d600a03a59 |
15 | 12808c6735ed |
hex | 93268d7fcdf |
10112112000223 has 2 divisors, whose sum is σ = 10112112000224. Its totient is φ = 10112112000222.
The previous prime is 10112112000217. The next prime is 10112112000241. The reversal of 10112112000223 is 32200021121101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10112112000223 - 217 = 10112111869151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10112112000197 and 10112112000206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10112112000283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056056000111 + 5056056000112.
It is an arithmetic number, because the mean of its divisors is an integer number (5056056000112).
Almost surely, 210112112000223 is an apocalyptic number.
10112112000223 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112112000223 is an equidigital number, since it uses as much as digits as its factorization.
10112112000223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10112112000223 its reverse (32200021121101), we get a palindrome (42312133121324).
The spelling of 10112112000223 in words is "ten trillion, one hundred twelve billion, one hundred twelve million, two hundred twenty-three", and thus it is an aban number.
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