Base | Representation |
---|---|
bin | 10110111111100000011001… |
… | …110100001010001001110111 |
3 | 111021001002100022220002210121 |
4 | 112333200121310022021313 |
5 | 101223232100114324003 |
6 | 555022224542432411 |
7 | 30204522123342442 |
oct | 2677403164121167 |
9 | 437032308802717 |
10 | 101121143120503 |
11 | 2a247266083580 |
12 | b411b56292707 |
13 | 44568b53967bc |
14 | 1ad840a326659 |
15 | ba55d653dcbd |
hex | 5bf819d0a277 |
101121143120503 has 32 divisors (see below), whose sum is σ = 111562779525120. Its totient is φ = 90893264041440.
The previous prime is 101121143120479. The next prime is 101121143120507. The reversal of 101121143120503 is 305021341121101.
It is a cyclic number.
It is not a de Polignac number, because 101121143120503 - 29 = 101121143119991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101121143120507) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1440785950 + ... + 1440856132.
It is an arithmetic number, because the mean of its divisors is an integer number (3486336860160).
Almost surely, 2101121143120503 is an apocalyptic number.
101121143120503 is a deficient number, since it is larger than the sum of its proper divisors (10441636404617).
101121143120503 is a wasteful number, since it uses less digits than its factorization.
101121143120503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74179.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 101121143120503 its reverse (305021341121101), we get a palindrome (406142484241604).
The spelling of 101121143120503 in words is "one hundred one trillion, one hundred twenty-one billion, one hundred forty-three million, one hundred twenty thousand, five hundred three".
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