101121200120177 has 2 divisors, whose sum is σ = 101121200120178. Its totient is φ = 101121200120176.

The previous prime is 101121200120147. The next prime is 101121200120179. The reversal of 101121200120177 is 771021002121101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98006059839601 + 3115140280576 = 9899801^2 + 1764976^2 .

It is an emirp because it is prime and its reverse (771021002121101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101121200120177 - 2¹² = 101121200116081 is a prime.

It is a super-2 number, since 2×101121200120177² (a number of 29 digits) contains 22 as substring.

Together with 101121200120179, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101121200120179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560600060088 + 50560600060089.

It is an arithmetic number, because the mean of its divisors is an integer number (50560600060089).

Almost surely, 2^{101121200120177} is an apocalyptic number.

It is an amenable number.

101121200120177 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121200120177 is an equidigital number, since it uses as much as digits as its factorization.

101121200120177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 392, while the sum is 26.

Adding to 101121200120177 its reverse (771021002121101), we get a palindrome (872142202241278).

The spelling of 101121200120177 in words is "one hundred one trillion, one hundred twenty-one billion, two hundred million, one hundred twenty thousand, one hundred seventy-seven".