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101121314251 = 1727121949493
BaseRepresentation
bin101111000101101001…
…1001100110111001011
3100200000022121000020011
41132023103030313023
53124044024024001
6114242100412351
710206610663156
oct1361323146713
9320008530204
10101121314251
11399813890a1
12177213a70b7
1396c6c13ab9
144c73d4ac9d
15296c8d0d51
hex178b4ccdcb

101121314251 has 8 divisors (see below), whose sum is σ = 107464722624. Its totient is φ = 94821805440.

The previous prime is 101121314237. The next prime is 101121314347. The reversal of 101121314251 is 152413121101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101121314251 - 27 = 101121314123 is a prime.

It is a super-3 number, since 3×1011213142513 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (101121314051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10970140 + ... + 10979353.

It is an arithmetic number, because the mean of its divisors is an integer number (13433090328).

Almost surely, 2101121314251 is an apocalyptic number.

101121314251 is a deficient number, since it is larger than the sum of its proper divisors (6343408373).

101121314251 is a wasteful number, since it uses less digits than its factorization.

101121314251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21949781.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 101121314251 its reverse (152413121101), we get a palindrome (253534435352).

The spelling of 101121314251 in words is "one hundred one billion, one hundred twenty-one million, three hundred fourteen thousand, two hundred fifty-one".

Divisors: 1 17 271 4607 21949493 373141381 5948312603 101121314251