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101121322213 is a prime number
BaseRepresentation
bin101111000101101001…
…1001110110011100101
3100200000022121102011001
41132023103032303211
53124044024302323
6114242100513301
710206611025322
oct1361323166345
9320008542131
10101121322213
113998139407a
12177213ab831
1396c6c17602
144c73d4db49
15296c8d33ad
hex178b4cece5

101121322213 has 2 divisors, whose sum is σ = 101121322214. Its totient is φ = 101121322212.

The previous prime is 101121322201. The next prime is 101121322229. The reversal of 101121322213 is 312223121101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76750053444 + 24371268769 = 277038^2 + 156113^2 .

It is an emirp because it is prime and its reverse (312223121101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101121322213 - 233 = 92531387621 is a prime.

It is a super-2 number, since 2×1011213222132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101121322243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560661106 + 50560661107.

It is an arithmetic number, because the mean of its divisors is an integer number (50560661107).

Almost surely, 2101121322213 is an apocalyptic number.

It is an amenable number.

101121322213 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121322213 is an equidigital number, since it uses as much as digits as its factorization.

101121322213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 101121322213 its reverse (312223121101), we get a palindrome (413344443314).

The spelling of 101121322213 in words is "one hundred one billion, one hundred twenty-one million, three hundred twenty-two thousand, two hundred thirteen".