Base | Representation |
---|---|
bin | 11101011011100010111… |
… | …10000001010111100101 |
3 | 10120200010201201210022001 |
4 | 32231301132001113211 |
5 | 113031440034304033 |
6 | 2052314251405301 |
7 | 133025666522413 |
oct | 16556136012745 |
9 | 3520121653261 |
10 | 1011221009893 |
11 | 35a946996796 |
12 | 143b93a53831 |
13 | 74485c25473 |
14 | 36d2c8082b3 |
15 | 1b48690ee7d |
hex | eb717815e5 |
1011221009893 has 2 divisors, whose sum is σ = 1011221009894. Its totient is φ = 1011221009892.
The previous prime is 1011221009857. The next prime is 1011221009917. The reversal of 1011221009893 is 3989001221101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 693983965249 + 317237044644 = 833057^2 + 563238^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011221009893 - 213 = 1011221001701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011221006893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505610504946 + 505610504947.
It is an arithmetic number, because the mean of its divisors is an integer number (505610504947).
Almost surely, 21011221009893 is an apocalyptic number.
It is an amenable number.
1011221009893 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011221009893 is an equidigital number, since it uses as much as digits as its factorization.
1011221009893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 37.
The spelling of 1011221009893 in words is "one trillion, eleven billion, two hundred twenty-one million, nine thousand, eight hundred ninety-three".
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