Base | Representation |
---|---|
bin | 11101011011100010111… |
… | …10011100010001111010 |
3 | 10120200010201221101111121 |
4 | 32231301132130101322 |
5 | 113031440101320442 |
6 | 2052314254015454 |
7 | 133026000461653 |
oct | 16556136342172 |
9 | 3520121841447 |
10 | 1011221120122 |
11 | 35a946a61594 |
12 | 143b93aa758a |
13 | 74485c636a5 |
14 | 36d2c83652a |
15 | 1b486932967 |
hex | eb7179c47a |
1011221120122 has 4 divisors (see below), whose sum is σ = 1516831680186. Its totient is φ = 505610560060.
The previous prime is 1011221120033. The next prime is 1011221120137. The reversal of 1011221120122 is 2210211221101.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 631899396241 + 379321723881 = 794921^2 + 615891^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1011221120096 and 1011221120105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252805280029 + ... + 252805280032.
Almost surely, 21011221120122 is an apocalyptic number.
1011221120122 is a deficient number, since it is larger than the sum of its proper divisors (505610560064).
1011221120122 is an equidigital number, since it uses as much as digits as its factorization.
1011221120122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 505610560063.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 1011221120122 its reverse (2210211221101), we get a palindrome (3221432341223).
The spelling of 1011221120122 in words is "one trillion, eleven billion, two hundred twenty-one million, one hundred twenty thousand, one hundred twenty-two".
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