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101122201241 = 719140642839
BaseRepresentation
bin101111000101101011…
…0100101011010011001
3100200000101021001221122
41132023112211122121
53124044240414431
6114242131415025
710206621346145
oct1361326453231
9320011231848
10101122201241
1139981934546
1217721754475
1396c7164749
144c740dc225
15296ca08a7b
hex178b5a5699

101122201241 has 4 divisors (see below), whose sum is σ = 101262844800. Its totient is φ = 100981557684.

The previous prime is 101122201237. The next prime is 101122201309. The reversal of 101122201241 is 142102221101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142102221101 = 1039136768259.

It is a cyclic number.

It is not a de Polignac number, because 101122201241 - 22 = 101122201237 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (101122201231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70320701 + ... + 70322138.

It is an arithmetic number, because the mean of its divisors is an integer number (25315711200).

Almost surely, 2101122201241 is an apocalyptic number.

It is an amenable number.

101122201241 is a deficient number, since it is larger than the sum of its proper divisors (140643559).

101122201241 is an equidigital number, since it uses as much as digits as its factorization.

101122201241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140643558.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 101122201241 its reverse (142102221101), we get a palindrome (243224422342).

The spelling of 101122201241 in words is "one hundred one billion, one hundred twenty-two million, two hundred one thousand, two hundred forty-one".

Divisors: 1 719 140642839 101122201241