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101122431403 = 729723486023
BaseRepresentation
bin101111000101101011…
…1011101100110101011
3100200000101200202200011
41132023113131212223
53124044320301103
6114242140352351
710206623325160
oct1361327354653
9320011622604
10101122431403
1139981a81464
12177218456b7
1396c7215436
144c7415c067
15296ca51d6d
hex178b5dd9ab

101122431403 has 8 divisors (see below), whose sum is σ = 115572619008. Its totient is φ = 86673275304.

The previous prime is 101122431353. The next prime is 101122431413. The reversal of 101122431403 is 304134221101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101122431403 - 29 = 101122430891 is a prime.

It is a super-2 number, since 2×1011224314032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (101122431413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34951 + ... + 451072.

It is an arithmetic number, because the mean of its divisors is an integer number (14446577376).

Almost surely, 2101122431403 is an apocalyptic number.

101122431403 is a deficient number, since it is larger than the sum of its proper divisors (14450187605).

101122431403 is an equidigital number, since it uses as much as digits as its factorization.

101122431403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 515753.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 101122431403 its reverse (304134221101), we get a palindrome (405256652504).

The spelling of 101122431403 in words is "one hundred one billion, one hundred twenty-two million, four hundred thirty-one thousand, four hundred three".

Divisors: 1 7 29723 208061 486023 3402161 14446061629 101122431403