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101122442013 = 333707480671
BaseRepresentation
bin101111000101101011…
…1100000001100011101
3100200000101201022020010
41132023113200030131
53124044321121023
6114242140513433
710206623401125
oct1361327401435
9320011638203
10101122442013
1139981a8942a
121772184b879
1396c721a208
144c74161c85
15296ca55093
hex178b5e031d

101122442013 has 4 divisors (see below), whose sum is σ = 134829922688. Its totient is φ = 67414961340.

The previous prime is 101122441961. The next prime is 101122442017. The reversal of 101122442013 is 310244221101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-101122442013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101122442017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16853740333 + ... + 16853740338.

It is an arithmetic number, because the mean of its divisors is an integer number (33707480672).

Almost surely, 2101122442013 is an apocalyptic number.

It is an amenable number.

101122442013 is a deficient number, since it is larger than the sum of its proper divisors (33707480675).

101122442013 is an equidigital number, since it uses as much as digits as its factorization.

101122442013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33707480674.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 101122442013 its reverse (310244221101), we get a palindrome (411366663114).

The spelling of 101122442013 in words is "one hundred one billion, one hundred twenty-two million, four hundred forty-two thousand, thirteen".

Divisors: 1 3 33707480671 101122442013