Base | Representation |
---|---|
bin | 101111000101101100… |
… | …1101101110011000001 |
3 | 100200000102210202211202 |
4 | 1132023121231303001 |
5 | 3124044443201032 |
6 | 114242201150545 |
7 | 10206631335113 |
oct | 1361331556301 |
9 | 320012722752 |
10 | 101123022017 |
11 | 39982345176 |
12 | 17721a8b455 |
13 | 96c7391204 |
14 | 4c742733b3 |
15 | 296cb1bd62 |
hex | 178b66dcc1 |
101123022017 has 2 divisors, whose sum is σ = 101123022018. Its totient is φ = 101123022016.
The previous prime is 101123021971. The next prime is 101123022019. The reversal of 101123022017 is 710220321101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89075983936 + 12047038081 = 298456^2 + 109759^2 .
It is a cyclic number.
It is not a de Polignac number, because 101123022017 - 28 = 101123021761 is a prime.
Together with 101123022019, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 101123022017.
It is not a weakly prime, because it can be changed into another prime (101123022019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561511008 + 50561511009.
It is an arithmetic number, because the mean of its divisors is an integer number (50561511009).
Almost surely, 2101123022017 is an apocalyptic number.
It is an amenable number.
101123022017 is a deficient number, since it is larger than the sum of its proper divisors (1).
101123022017 is an equidigital number, since it uses as much as digits as its factorization.
101123022017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 101123022017 its reverse (710220321101), we get a palindrome (811343343118).
The spelling of 101123022017 in words is "one hundred one billion, one hundred twenty-three million, twenty-two thousand, seventeen".
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