10112311117 has 2 divisors, whose sum is σ = 10112311118. Its totient is φ = 10112311116.

The previous prime is 10112311109. The next prime is 10112311171. The reversal of 10112311117 is 71111321101.

Together with next prime (10112311171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8974530756 + 1137780361 = 94734^2 + 33731^2 .

It is a cyclic number.

It is not a de Polignac number, because 10112311117 - 2³ = 10112311109 is a prime.

It is a super-2 number, since 2×10112311117² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10112311094 and 10112311103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112311177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056155558 + 5056155559.

It is an arithmetic number, because the mean of its divisors is an integer number (5056155559).

Almost surely, 2^10112311117 is an apocalyptic number.

It is an amenable number.

10112311117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112311117 is an equidigital number, since it uses as much as digits as its factorization.

10112311117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 19.

Adding to 10112311117 its reverse (71111321101), we get a palindrome (81223632218).

The spelling of 10112311117 in words is "ten billion, one hundred twelve million, three hundred eleven thousand, one hundred seventeen".