Base | Representation |
---|---|
bin | 1001001100100111010011… |
… | …1001110100110010000011 |
3 | 1022210201122120110101110101 |
4 | 2103021310321310302003 |
5 | 2311140004432031433 |
6 | 33301311050543231 |
7 | 2062406401402246 |
oct | 223116471646203 |
9 | 38721576411411 |
10 | 10112314330243 |
11 | 32496768a2754 |
12 | 1173a01737b17 |
13 | 584782c770b8 |
14 | 26d61d83125d |
15 | 1280a02dd07d |
hex | 93274e74c83 |
10112314330243 has 2 divisors, whose sum is σ = 10112314330244. Its totient is φ = 10112314330242.
The previous prime is 10112314330231. The next prime is 10112314330249. The reversal of 10112314330243 is 34203341321101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10112314330243 - 217 = 10112314199171 is a prime.
It is a super-2 number, since 2×101123143302432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10112314330249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056157165121 + 5056157165122.
It is an arithmetic number, because the mean of its divisors is an integer number (5056157165122).
Almost surely, 210112314330243 is an apocalyptic number.
10112314330243 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112314330243 is an equidigital number, since it uses as much as digits as its factorization.
10112314330243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 10112314330243 its reverse (34203341321101), we get a palindrome (44315655651344).
The spelling of 10112314330243 in words is "ten trillion, one hundred twelve billion, three hundred fourteen million, three hundred thirty thousand, two hundred forty-three".
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