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10112314330243 is a prime number
BaseRepresentation
bin1001001100100111010011…
…1001110100110010000011
31022210201122120110101110101
42103021310321310302003
52311140004432031433
633301311050543231
72062406401402246
oct223116471646203
938721576411411
1010112314330243
1132496768a2754
121173a01737b17
13584782c770b8
1426d61d83125d
151280a02dd07d
hex93274e74c83

10112314330243 has 2 divisors, whose sum is σ = 10112314330244. Its totient is φ = 10112314330242.

The previous prime is 10112314330231. The next prime is 10112314330249. The reversal of 10112314330243 is 34203341321101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10112314330243 - 217 = 10112314199171 is a prime.

It is a super-2 number, since 2×101123143302432 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10112314330249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056157165121 + 5056157165122.

It is an arithmetic number, because the mean of its divisors is an integer number (5056157165122).

Almost surely, 210112314330243 is an apocalyptic number.

10112314330243 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112314330243 is an equidigital number, since it uses as much as digits as its factorization.

10112314330243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 10112314330243 its reverse (34203341321101), we get a palindrome (44315655651344).

The spelling of 10112314330243 in words is "ten trillion, one hundred twelve billion, three hundred fourteen million, three hundred thirty thousand, two hundred forty-three".