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101123231313053 is a prime number
BaseRepresentation
bin10110111111100010010110…
…010001111110110010011101
3111021001021201212012021110102
4112333202112101332302131
5101223300334204004203
6555023212055550445
730204624640601405
oct2677422621766235
9437037655167412
10101123231313053
112a248137887544
12b41243968b425
134456b58bac1b1
141ad85677bb805
15ba56a9a22888
hex5bf89647ec9d

101123231313053 has 2 divisors, whose sum is σ = 101123231313054. Its totient is φ = 101123231313052.

The previous prime is 101123231312981. The next prime is 101123231313067. The reversal of 101123231313053 is 350313132321101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55908190843684 + 45215040469369 = 7477178^2 + 6724213^2 .

It is a cyclic number.

It is not a de Polignac number, because 101123231313053 - 210 = 101123231312029 is a prime.

It is a super-2 number, since 2×1011232313130532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101123231310053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561615656526 + 50561615656527.

It is an arithmetic number, because the mean of its divisors is an integer number (50561615656527).

Almost surely, 2101123231313053 is an apocalyptic number.

It is an amenable number.

101123231313053 is a deficient number, since it is larger than the sum of its proper divisors (1).

101123231313053 is an equidigital number, since it uses as much as digits as its factorization.

101123231313053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 101123231313053 its reverse (350313132321101), we get a palindrome (451436363634154).

The spelling of 101123231313053 in words is "one hundred one trillion, one hundred twenty-three billion, two hundred thirty-one million, three hundred thirteen thousand, fifty-three".