Base | Representation |
---|---|
bin | 1001001100100111101010… |
… | …1100010010000000101011 |
3 | 1022210201220100012020110011 |
4 | 2103021322230102000223 |
5 | 2311140204312140433 |
6 | 33301324440232351 |
7 | 2062411661011444 |
oct | 223117254220053 |
9 | 38721810166404 |
10 | 10112411443243 |
11 | 32497166a212a |
12 | 1173a2a16b6b7 |
13 | 58479a119805 |
14 | 26d62c6b02cb |
15 | 1280a8ac23cd |
hex | 9327ab1202b |
10112411443243 has 2 divisors, whose sum is σ = 10112411443244. Its totient is φ = 10112411443242.
The previous prime is 10112411443241. The next prime is 10112411443271. The reversal of 10112411443243 is 34234411421101.
It is a weak prime.
It is an emirp because it is prime and its reverse (34234411421101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10112411443243 - 21 = 10112411443241 is a prime.
Together with 10112411443241, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10112411443241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056205721621 + 5056205721622.
It is an arithmetic number, because the mean of its divisors is an integer number (5056205721622).
Almost surely, 210112411443243 is an apocalyptic number.
10112411443243 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112411443243 is an equidigital number, since it uses as much as digits as its factorization.
10112411443243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 10112411443243 its reverse (34234411421101), we get a palindrome (44346822864344).
The spelling of 10112411443243 in words is "ten trillion, one hundred twelve billion, four hundred eleven million, four hundred forty-three thousand, two hundred forty-three".
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