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10112834713 is a prime number
BaseRepresentation
bin10010110101100010…
…11001110010011001
3222002210002020020211
421122301121302121
5131202341202323
64351253051121
7505414451062
oct113261316231
928083066224
1010112834713
11431a482443
121b62926aa1
13c521a5b87
146bd135569
153e2c4a70d
hex25ac59c99

10112834713 has 2 divisors, whose sum is σ = 10112834714. Its totient is φ = 10112834712.

The previous prime is 10112834707. The next prime is 10112834717. The reversal of 10112834713 is 31743821101.

10112834713 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5728673344 + 4384161369 = 75688^2 + 66213^2 .

It is a cyclic number.

It is not a de Polignac number, because 10112834713 - 229 = 9575963801 is a prime.

It is not a weakly prime, because it can be changed into another prime (10112834717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056417356 + 5056417357.

It is an arithmetic number, because the mean of its divisors is an integer number (5056417357).

Almost surely, 210112834713 is an apocalyptic number.

It is an amenable number.

10112834713 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112834713 is an equidigital number, since it uses as much as digits as its factorization.

10112834713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

The spelling of 10112834713 in words is "ten billion, one hundred twelve million, eight hundred thirty-four thousand, seven hundred thirteen".