101130032011 has 4 divisors (see below), whose sum is σ = 101449054512. Its totient is φ = 100811009512.

The previous prime is 101130031963. The next prime is 101130032057. The reversal of 101130032011 is 110230031101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110230031101 = 109 ⋅1011284689.

It is a cyclic number.

It is not a de Polignac number, because 101130032011 - 2¹¹ = 101130029963 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101130031982 and 101130032000.

It is not an unprimeable number, because it can be changed into a prime (101130032611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159510775 + ... + 159511408.

It is an arithmetic number, because the mean of its divisors is an integer number (25362263628).

Almost surely, 2^101130032011 is an apocalyptic number.

101130032011 is a deficient number, since it is larger than the sum of its proper divisors (319022501).

101130032011 is an equidigital number, since it uses as much as digits as its factorization.

101130032011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 319022500.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 101130032011 its reverse (110230031101), we get a palindrome (211360063112).

The spelling of 101130032011 in words is "one hundred one billion, one hundred thirty million, thirty-two thousand, eleven".