10113004025 has 6 divisors (see below), whose sum is σ = 12540125022. Its totient is φ = 8090403200.

The previous prime is 10113004009. The next prime is 10113004073. The reversal of 10113004025 is 52040031101.

10113004025 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 3374564281 + 6738439744 = 58091^2 + 82088^2 .

It is not a de Polignac number, because 10113004025 - 2⁴ = 10113004009 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10113003994 and 10113004012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 202260056 + ... + 202260105.

It is an arithmetic number, because the mean of its divisors is an integer number (2090020837).

Almost surely, 2^10113004025 is an apocalyptic number.

It is an amenable number.

10113004025 is a deficient number, since it is larger than the sum of its proper divisors (2427120997).

10113004025 is an equidigital number, since it uses as much as digits as its factorization.

10113004025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 404520171 (or 404520166 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 10113004025 its reverse (52040031101), we get a palindrome (62153035126).

The spelling of 10113004025 in words is "ten billion, one hundred thirteen million, four thousand, twenty-five".