10113005052145 has 4 divisors (see below), whose sum is σ = 12135606062580. Its totient is φ = 8090404041712.

The previous prime is 10113005052131. The next prime is 10113005052149. The reversal of 10113005052145 is 54125050031101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6406082488576 + 3706922563569 = 2531024^2 + 1925337^2 .

It is a cyclic number.

It is not a de Polignac number, because 10113005052145 - 2¹¹ = 10113005050097 is a prime.

It is a super-3 number, since 3×10113005052145³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (10113005052149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1011300505210 + ... + 1011300505219.

It is an arithmetic number, because the mean of its divisors is an integer number (3033901515645).

Almost surely, 2^{10113005052145} is an apocalyptic number.

It is an amenable number.

10113005052145 is a deficient number, since it is larger than the sum of its proper divisors (2022601010435).

10113005052145 is an equidigital number, since it uses as much as digits as its factorization.

10113005052145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2022601010434.

The product of its (nonzero) digits is 3000, while the sum is 28.

Adding to 10113005052145 its reverse (54125050031101), we get a palindrome (64238055083246).

The spelling of 10113005052145 in words is "ten trillion, one hundred thirteen billion, five million, fifty-two thousand, one hundred forty-five".