Base | Representation |
---|---|
bin | 101111000101111010… |
… | …0110000100100000001 |
3 | 100200000221010221102022 |
4 | 1132023310300210001 |
5 | 3124103302024413 |
6 | 114243013131225 |
7 | 10210045522304 |
oct | 1361364604401 |
9 | 320027127368 |
10 | 101130111233 |
11 | 39986347428 |
12 | 17724329b15 |
13 | 96c89a3c08 |
14 | 4c7519ab3b |
15 | 296d56c608 |
hex | 178bd30901 |
101130111233 has 2 divisors, whose sum is σ = 101130111234. Its totient is φ = 101130111232.
The previous prime is 101130111221. The next prime is 101130111253. The reversal of 101130111233 is 332111031101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90220935424 + 10909175809 = 300368^2 + 104447^2 .
It is an emirp because it is prime and its reverse (332111031101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101130111233 - 24 = 101130111217 is a prime.
It is not a weakly prime, because it can be changed into another prime (101130111253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565055616 + 50565055617.
It is an arithmetic number, because the mean of its divisors is an integer number (50565055617).
Almost surely, 2101130111233 is an apocalyptic number.
It is an amenable number.
101130111233 is a deficient number, since it is larger than the sum of its proper divisors (1).
101130111233 is an equidigital number, since it uses as much as digits as its factorization.
101130111233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 101130111233 its reverse (332111031101), we get a palindrome (433241142334).
The spelling of 101130111233 in words is "one hundred one billion, one hundred thirty million, one hundred eleven thousand, two hundred thirty-three".
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