10113011133 has 4 divisors (see below), whose sum is σ = 13484014848. Its totient is φ = 6742007420.

The previous prime is 10113011113. The next prime is 10113011137. The reversal of 10113011133 is 33111031101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33111031101 = 3 ⋅11037010367.

It is a cyclic number.

It is not a de Polignac number, because 10113011133 - 2¹⁷ = 10112880061 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113011137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685501853 + ... + 1685501858.

It is an arithmetic number, because the mean of its divisors is an integer number (3371003712).

Almost surely, 2^10113011133 is an apocalyptic number.

It is an amenable number.

10113011133 is a deficient number, since it is larger than the sum of its proper divisors (3371003715).

10113011133 is an equidigital number, since it uses as much as digits as its factorization.

10113011133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3371003714.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 10113011133 its reverse (33111031101), we get a palindrome (43224042234).

The spelling of 10113011133 in words is "ten billion, one hundred thirteen million, eleven thousand, one hundred thirty-three".