Base | Representation |
---|---|
bin | 10010110101100100… |
… | …00100111000100001 |
3 | 222002210102012101121 |
4 | 21122302010320201 |
5 | 131202412324413 |
6 | 4351300532241 |
7 | 505416114523 |
oct | 113262047041 |
9 | 28083365347 |
10 | 10113011233 |
11 | 431a593026 |
12 | 1b629b1081 |
13 | c52238320 |
14 | 6bd17da13 |
15 | 3e2c82b8d |
hex | 25ac84e21 |
10113011233 has 4 divisors (see below), whose sum is σ = 10890935188. Its totient is φ = 9335087280.
The previous prime is 10113011219. The next prime is 10113011257. The reversal of 10113011233 is 33211031101.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1732890384 + 8380120849 = 41628^2 + 91543^2 .
It is a cyclic number.
It is not a de Polignac number, because 10113011233 - 213 = 10113003041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10113011203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388961958 + ... + 388961983.
It is an arithmetic number, because the mean of its divisors is an integer number (2722733797).
Almost surely, 210113011233 is an apocalyptic number.
10113011233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10113011233 is a deficient number, since it is larger than the sum of its proper divisors (777923955).
10113011233 is an equidigital number, since it uses as much as digits as its factorization.
10113011233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 777923954.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 10113011233 its reverse (33211031101), we get a palindrome (43324042334).
The spelling of 10113011233 in words is "ten billion, one hundred thirteen million, eleven thousand, two hundred thirty-three".
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