101130312013 has 2 divisors, whose sum is σ = 101130312014. Its totient is φ = 101130312012.

The previous prime is 101130311959. The next prime is 101130312037. The reversal of 101130312013 is 310213031101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80416482084 + 20713829929 = 283578^2 + 143923^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101130312013 is a prime.

It is a super-2 number, since 2×101130312013² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101130312043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565156006 + 50565156007.

It is an arithmetic number, because the mean of its divisors is an integer number (50565156007).

Almost surely, 2^101130312013 is an apocalyptic number.

It is an amenable number.

101130312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101130312013 is an equidigital number, since it uses as much as digits as its factorization.

101130312013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 101130312013 its reverse (310213031101), we get a palindrome (411343343114).

The spelling of 101130312013 in words is "one hundred one billion, one hundred thirty million, three hundred twelve thousand, thirteen".