101130433443330 has 32 divisors (see below), whose sum is σ = 243273578494464. Its totient is φ = 26905833559296.

The previous prime is 101130433443317. The next prime is 101130433443341. The reversal of 101130433443330 is 33344334031101.

It is a junction number, because it is equal to n+sod(n) for n = 101130433443291 and 101130433443300.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3892613394 + ... + 3892639373.

It is an arithmetic number, because the mean of its divisors is an integer number (7602299327952).

Almost surely, 2^{101130433443330} is an apocalyptic number.

101130433443330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101130433443330 is an abundant number, since it is smaller than the sum of its proper divisors (142143145051134).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101130433443330 is a wasteful number, since it uses less digits than its factorization.

101130433443330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7785253210.

The product of its (nonzero) digits is 46656, while the sum is 33.

Adding to 101130433443330 its reverse (33344334031101), we get a palindrome (134474767474431).

The spelling of 101130433443330 in words is "one hundred one trillion, one hundred thirty billion, four hundred thirty-three million, four hundred forty-three thousand, three hundred thirty".