10113044331 has 24 divisors (see below), whose sum is σ = 14737619520. Its totient is φ = 6165216096.

The previous prime is 10113044323. The next prime is 10113044341. The reversal of 10113044331 is 13344031101.

It is not a de Polignac number, because 10113044331 - 2³ = 10113044323 is a prime.

It is a super-2 number, since 2×10113044331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10113044298 and 10113044307.

It is not an unprimeable number, because it can be changed into a prime (10113044341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38961 + ... + 147458.

It is an arithmetic number, because the mean of its divisors is an integer number (614067480).

Almost surely, 2^10113044331 is an apocalyptic number.

10113044331 is a deficient number, since it is larger than the sum of its proper divisors (4624575189).

10113044331 is a wasteful number, since it uses less digits than its factorization.

10113044331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 186555 (or 186542 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10113044331 its reverse (13344031101), we get a palindrome (23457075432).

The spelling of 10113044331 in words is "ten billion, one hundred thirteen million, forty-four thousand, three hundred thirty-one".