Base | Representation |
---|---|
bin | 10010110101100100… |
… | …11010100111010001 |
3 | 222002210120201111012 |
4 | 21122302122213101 |
5 | 131202423201431 |
6 | 4351302500305 |
7 | 505416635156 |
oct | 113262324721 |
9 | 28083521435 |
10 | 10113100241 |
11 | 431a643992 |
12 | 1b62a34695 |
13 | c522699aa |
14 | 6bd1a422d |
15 | 3e2c9e22b |
hex | 25ac9a9d1 |
10113100241 has 2 divisors, whose sum is σ = 10113100242. Its totient is φ = 10113100240.
The previous prime is 10113100237. The next prime is 10113100247. The reversal of 10113100241 is 14200131101.
10113100241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10077148225 + 35952016 = 100385^2 + 5996^2 .
It is a cyclic number.
It is not a de Polignac number, because 10113100241 - 22 = 10113100237 is a prime.
It is not a weakly prime, because it can be changed into another prime (10113100247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056550120 + 5056550121.
It is an arithmetic number, because the mean of its divisors is an integer number (5056550121).
Almost surely, 210113100241 is an apocalyptic number.
It is an amenable number.
10113100241 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113100241 is an equidigital number, since it uses as much as digits as its factorization.
10113100241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 10113100241 its reverse (14200131101), we get a palindrome (24313231342).
The spelling of 10113100241 in words is "ten billion, one hundred thirteen million, one hundred thousand, two hundred forty-one".
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