Search a number
-
+
101131007 = 788312829
BaseRepresentation
bin1100000011100…
…10001011111111
321001021222122212
412001302023333
5201342143012
614011331035
72335412405
oct601621377
9231258585
10101131007
11520a424a
1229a50a7b
1317c4b543
14d607475
158d29b22
hex60722ff

101131007 has 4 divisors (see below), whose sum is σ = 101151720. Its totient is φ = 101110296.

The previous prime is 101131003. The next prime is 101131013. The reversal of 101131007 is 700131101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101131007 - 22 = 101131003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101130982 and 101131000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101131003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1469 + ... + 14297.

It is an arithmetic number, because the mean of its divisors is an integer number (25287930).

Almost surely, 2101131007 is an apocalyptic number.

101131007 is a deficient number, since it is larger than the sum of its proper divisors (20713).

101131007 is an equidigital number, since it uses as much as digits as its factorization.

101131007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20712.

The product of its (nonzero) digits is 21, while the sum is 14.

The square root of 101131007 is about 10056.3913507779. The cubic root of 101131007 is about 465.9022171987.

Adding to 101131007 its reverse (700131101), we get a palindrome (801262108).

The spelling of 101131007 in words is "one hundred one million, one hundred thirty-one thousand, seven".

Divisors: 1 7883 12829 101131007