Base | Representation |
---|---|
bin | 10010110101100100… |
… | …11011010011101001 |
3 | 222002210120212101101 |
4 | 21122302123103221 |
5 | 131202423244311 |
6 | 4351302521401 |
7 | 505416646354 |
oct | 113262332351 |
9 | 28083525341 |
10 | 10113103081 |
11 | 431a646034 |
12 | 1b62a36261 |
13 | c5226b083 |
14 | 6bd1a529b |
15 | 3e2c9eec1 |
hex | 25ac9b4e9 |
10113103081 has 2 divisors, whose sum is σ = 10113103082. Its totient is φ = 10113103080.
The previous prime is 10113103069. The next prime is 10113103109. The reversal of 10113103081 is 18030131101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8122515625 + 1990587456 = 90125^2 + 44616^2 .
It is an emirp because it is prime and its reverse (18030131101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10113103081 - 221 = 10111005929 is a prime.
It is a super-2 number, since 2×101131030812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10113133081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056551540 + 5056551541.
It is an arithmetic number, because the mean of its divisors is an integer number (5056551541).
Almost surely, 210113103081 is an apocalyptic number.
It is an amenable number.
10113103081 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113103081 is an equidigital number, since it uses as much as digits as its factorization.
10113103081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 10113103081 its reverse (18030131101), we get a palindrome (28143234182).
The spelling of 10113103081 in words is "ten billion, one hundred thirteen million, one hundred three thousand, eighty-one".
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