Base | Representation |
---|---|
bin | 101111000101111100… |
… | …0100110111010001111 |
3 | 100200001000001012120002 |
4 | 1132023320212322033 |
5 | 3124104031322041 |
6 | 114243050514515 |
7 | 10210060224146 |
oct | 1361370467217 |
9 | 320030035502 |
10 | 101131120271 |
11 | 39986976545 |
12 | 17724735a3b |
13 | 96c8c6828c |
14 | 4c7538075d |
15 | 296d6bb59b |
hex | 178be26e8f |
101131120271 has 2 divisors, whose sum is σ = 101131120272. Its totient is φ = 101131120270.
The previous prime is 101131120213. The next prime is 101131120301. The reversal of 101131120271 is 172021131101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101131120271 is a prime.
It is a super-2 number, since 2×1011311202712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101131120471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565560135 + 50565560136.
It is an arithmetic number, because the mean of its divisors is an integer number (50565560136).
Almost surely, 2101131120271 is an apocalyptic number.
101131120271 is a deficient number, since it is larger than the sum of its proper divisors (1).
101131120271 is an equidigital number, since it uses as much as digits as its factorization.
101131120271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 20.
Adding to 101131120271 its reverse (172021131101), we get a palindrome (273152251372).
The spelling of 101131120271 in words is "one hundred one billion, one hundred thirty-one million, one hundred twenty thousand, two hundred seventy-one".
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