Base | Representation |
---|---|
bin | 10010110101100100… |
… | …11101100101010001 |
3 | 222002210121100011120 |
4 | 21122302131211101 |
5 | 131202424044101 |
6 | 4351303032453 |
7 | 505420015500 |
oct | 113262354521 |
9 | 28083540146 |
10 | 10113112401 |
11 | 431a652037 |
12 | 1b62a3b729 |
13 | c522723a2 |
14 | 6bd1a8837 |
15 | 3e2ca2b36 |
hex | 25ac9d951 |
10113112401 has 24 divisors (see below), whose sum is σ = 15706429344. Its totient is φ = 5771263680.
The previous prime is 10113112393. The next prime is 10113112417. The reversal of 10113112401 is 10421131101.
10113112401 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10113112401 - 23 = 10113112393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10113112421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 66666 + ... + 157068.
It is an arithmetic number, because the mean of its divisors is an integer number (654434556).
Almost surely, 210113112401 is an apocalyptic number.
It is an amenable number.
10113112401 is a deficient number, since it is larger than the sum of its proper divisors (5593316943).
10113112401 is an equidigital number, since it uses as much as digits as its factorization.
10113112401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91181 (or 91174 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 10113112401 its reverse (10421131101), we get a palindrome (20534243502).
The spelling of 10113112401 in words is "ten billion, one hundred thirteen million, one hundred twelve thousand, four hundred one".
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