Base | Representation |
---|---|
bin | 10010110101100100… |
… | …11101101111010111 |
3 | 222002210121101001111 |
4 | 21122302131233113 |
5 | 131202424104142 |
6 | 4351303035451 |
7 | 505420020412 |
oct | 113262355727 |
9 | 28083541044 |
10 | 10113113047 |
11 | 431a652574 |
12 | 1b62a3bb87 |
13 | c5227277b |
14 | 6bd1a8b79 |
15 | 3e2ca2e17 |
hex | 25ac9dbd7 |
10113113047 has 2 divisors, whose sum is σ = 10113113048. Its totient is φ = 10113113046.
The previous prime is 10113113027. The next prime is 10113113053. The reversal of 10113113047 is 74031131101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10113113047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10113113027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056556523 + 5056556524.
It is an arithmetic number, because the mean of its divisors is an integer number (5056556524).
Almost surely, 210113113047 is an apocalyptic number.
10113113047 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113113047 is an equidigital number, since it uses as much as digits as its factorization.
10113113047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 10113113047 its reverse (74031131101), we get a palindrome (84144244148).
The spelling of 10113113047 in words is "ten billion, one hundred thirteen million, one hundred thirteen thousand, forty-seven".
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