10113141121 has 2 divisors, whose sum is σ = 10113141122. Its totient is φ = 10113141120.

The previous prime is 10113141119. The next prime is 10113141131. The reversal of 10113141121 is 12114131101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8823972096 + 1289169025 = 93936^2 + 35905^2 .

It is an emirp because it is prime and its reverse (12114131101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10113141121 - 2¹ = 10113141119 is a prime.

It is a super-2 number, since 2×10113141121² (a number of 21 digits) contains 22 as substring.

Together with 10113141119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10113141095 and 10113141104.

It is not a weakly prime, because it can be changed into another prime (10113141131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056570560 + 5056570561.

It is an arithmetic number, because the mean of its divisors is an integer number (5056570561).

Almost surely, 2^10113141121 is an apocalyptic number.

It is an amenable number.

10113141121 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113141121 is an equidigital number, since it uses as much as digits as its factorization.

10113141121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 10113141121 its reverse (12114131101), we get a palindrome (22227272222).

The spelling of 10113141121 in words is "ten billion, one hundred thirteen million, one hundred forty-one thousand, one hundred twenty-one".