10113213169 has 2 divisors, whose sum is σ = 10113213170. Its totient is φ = 10113213168.

The previous prime is 10113213167. The next prime is 10113213199. The reversal of 10113213169 is 96131231101.

10113213169 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8998988769 + 1114224400 = 94863^2 + 33380^2 .

It is a cyclic number.

It is not a de Polignac number, because 10113213169 - 2¹ = 10113213167 is a prime.

It is a super-2 number, since 2×10113213169² (a number of 21 digits) contains 22 as substring.

Together with 10113213167, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10113213167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056606584 + 5056606585.

It is an arithmetic number, because the mean of its divisors is an integer number (5056606585).

Almost surely, 2^10113213169 is an apocalyptic number.

It is an amenable number.

10113213169 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113213169 is an equidigital number, since it uses as much as digits as its factorization.

10113213169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 10113213169 in words is "ten billion, one hundred thirteen million, two hundred thirteen thousand, one hundred sixty-nine".