101132141540134 has 8 divisors (see below), whose sum is σ = 159682328747640. Its totient is φ = 47904698624256.

The previous prime is 101132141540119. The next prime is 101132141540149. The reversal of 101132141540134 is 431045141231101.

It is an interprime number because it is at equal distance from previous prime (101132141540119) and next prime (101132141540149).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 101132141540096 and 101132141540105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1330686072859 + ... + 1330686072934.

It is an arithmetic number, because the mean of its divisors is an integer number (19960291093455).

Almost surely, 2^{101132141540134} is an apocalyptic number.

101132141540134 is a deficient number, since it is larger than the sum of its proper divisors (58550187207506).

101132141540134 is a wasteful number, since it uses less digits than its factorization.

101132141540134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2661372145814.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 101132141540134 its reverse (431045141231101), we get a palindrome (532177282771235).

The spelling of 101132141540134 in words is "one hundred one trillion, one hundred thirty-two billion, one hundred forty-one million, five hundred forty thousand, one hundred thirty-four".