101132142114413 has 4 divisors (see below), whose sum is σ = 101160383431068. Its totient is φ = 101103900797760.

The previous prime is 101132142114373. The next prime is 101132142114463. The reversal of 101132142114413 is 314411241231101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 79022463533764 + 22109678580649 = 8889458^2 + 4702093^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101132142114413 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101132142114463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14120652956 + ... + 14120660117.

It is an arithmetic number, because the mean of its divisors is an integer number (25290095857767).

Almost surely, 2^{101132142114413} is an apocalyptic number.

It is an amenable number.

101132142114413 is a deficient number, since it is larger than the sum of its proper divisors (28241316655).

101132142114413 is an equidigital number, since it uses as much as digits as its factorization.

101132142114413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28241316654.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 101132142114413 its reverse (314411241231101), we get a palindrome (415543383345514).

The spelling of 101132142114413 in words is "one hundred one trillion, one hundred thirty-two billion, one hundred forty-two million, one hundred fourteen thousand, four hundred thirteen".