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1011321601323 = 311214991858579
BaseRepresentation
bin11101011011101110111…
…01101111110100101011
310120200101202000100210120
432231313131233310223
5113032141312220243
62052332243414323
7133031330530035
oct16556735576453
93520352010716
101011321601323
1135a998751600
121440016843a3
13744a0a15217
1436d3bd10c55
151b49067ec83
hexeb7776fd2b

1011321601323 has 24 divisors (see below), whose sum is σ = 1483146840000. Its totient is φ = 612512965680.

The previous prime is 1011321601307. The next prime is 1011321601331. The reversal of 1011321601323 is 3231061231101.

It is not a de Polignac number, because 1011321601323 - 24 = 1011321601307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1011321601293 and 1011321601302.

It is not an unprimeable number, because it can be changed into a prime (1011321609323) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 385153 + ... + 1473426.

It is an arithmetic number, because the mean of its divisors is an integer number (61797785000).

Almost surely, 21011321601323 is an apocalyptic number.

1011321601323 is a deficient number, since it is larger than the sum of its proper divisors (471825238677).

1011321601323 is a wasteful number, since it uses less digits than its factorization.

1011321601323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1860103 (or 1860092 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 1011321601323 its reverse (3231061231101), we get a palindrome (4242382832424).

The spelling of 1011321601323 in words is "one trillion, eleven billion, three hundred twenty-one million, six hundred one thousand, three hundred twenty-three".

Divisors: 1 3 11 33 121 363 1499 4497 16489 49467 181379 544137 1858579 5575737 20444369 61333107 224888059 674664177 2786009921 8358029763 30646109131 91938327393 337107200441 1011321601323