Base | Representation |
---|---|
bin | 11101011011101110111… |
… | …11010001010011110111 |
3 | 10120200101202202122112202 |
4 | 32231313133101103313 |
5 | 113032141413010011 |
6 | 2052332300135115 |
7 | 133031334112145 |
oct | 16556737212367 |
9 | 3520352678482 |
10 | 1011322000631 |
11 | 35a9989a4608 |
12 | 14400183749b |
13 | 744a0b24bb7 |
14 | 36d3bdb6595 |
15 | 1b49070d23b |
hex | eb777d14f7 |
1011322000631 has 2 divisors, whose sum is σ = 1011322000632. Its totient is φ = 1011322000630.
The previous prime is 1011322000543. The next prime is 1011322000693. The reversal of 1011322000631 is 1360002231101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011322000631 - 222 = 1011317806327 is a prime.
It is a super-2 number, since 2×10113220006312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011322060631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505661000315 + 505661000316.
It is an arithmetic number, because the mean of its divisors is an integer number (505661000316).
Almost surely, 21011322000631 is an apocalyptic number.
1011322000631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011322000631 is an equidigital number, since it uses as much as digits as its factorization.
1011322000631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1011322000631 its reverse (1360002231101), we get a palindrome (2371324231732).
The spelling of 1011322000631 in words is "one trillion, eleven billion, three hundred twenty-two million, six hundred thirty-one", and thus it is an aban number.
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