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1011322001113 is a prime number
BaseRepresentation
bin11101011011101110111…
…11010001011011011001
310120200101202202200012121
432231313133101123121
5113032141413013423
62052332300141241
7133031334113434
oct16556737213331
93520352680177
101011322001113
1135a9989a4a06
12144001837821
13744a0b25198
1436d3bdb681b
151b49070d45d
hexeb777d16d9

1011322001113 has 2 divisors, whose sum is σ = 1011322001114. Its totient is φ = 1011322001112.

The previous prime is 1011322001093. The next prime is 1011322001149. The reversal of 1011322001113 is 3111002231101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 617494212864 + 393827788249 = 785808^2 + 627557^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011322001113 - 237 = 873883047641 is a prime.

It is not a weakly prime, because it can be changed into another prime (1011322001713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505661000556 + 505661000557.

It is an arithmetic number, because the mean of its divisors is an integer number (505661000557).

Almost surely, 21011322001113 is an apocalyptic number.

It is an amenable number.

1011322001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011322001113 is an equidigital number, since it uses as much as digits as its factorization.

1011322001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1011322001113 its reverse (3111002231101), we get a palindrome (4122324232214).

The spelling of 1011322001113 in words is "one trillion, eleven billion, three hundred twenty-two million, one thousand, one hundred thirteen".