Base | Representation |
---|---|
bin | 11101011011101110111… |
… | …11101100110100100001 |
3 | 10120200101202222101010011 |
4 | 32231313133230310201 |
5 | 113032141430111223 |
6 | 2052332302404521 |
7 | 133031335061521 |
oct | 16556737546441 |
9 | 3520352871104 |
10 | 1011322113313 |
11 | 35a998a71236 |
12 | 144001890741 |
13 | 744a0b64285 |
14 | 36d3c005681 |
15 | 1b49073180d |
hex | eb777ecd21 |
1011322113313 has 4 divisors (see below), whose sum is σ = 1013962641408. Its totient is φ = 1008681585220.
The previous prime is 1011322113301. The next prime is 1011322113391. The reversal of 1011322113313 is 3133112231101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1011322113313 - 237 = 873883159841 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1011322113913) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320263473 + ... + 1320264238.
It is an arithmetic number, because the mean of its divisors is an integer number (253490660352).
Almost surely, 21011322113313 is an apocalyptic number.
It is an amenable number.
1011322113313 is a deficient number, since it is larger than the sum of its proper divisors (2640528095).
1011322113313 is an equidigital number, since it uses as much as digits as its factorization.
1011322113313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2640528094.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1011322113313 its reverse (3133112231101), we get a palindrome (4144434344414).
The spelling of 1011322113313 in words is "one trillion, eleven billion, three hundred twenty-two million, one hundred thirteen thousand, three hundred thirteen".
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