Base | Representation |
---|---|
bin | 11101011011101111111… |
… | …01110100110001110111 |
3 | 10120200102022211120122121 |
4 | 32231313331310301313 |
5 | 113032200440311411 |
6 | 2052333143540411 |
7 | 133031462151562 |
oct | 16556775646167 |
9 | 3520368746577 |
10 | 1011330010231 |
11 | 35a9a2475312 |
12 | 14400445a707 |
13 | 744a269a7c8 |
14 | 36d3d09d4d9 |
15 | 1b491291571 |
hex | eb77f74c77 |
1011330010231 has 2 divisors, whose sum is σ = 1011330010232. Its totient is φ = 1011330010230.
The previous prime is 1011330010213. The next prime is 1011330010237. The reversal of 1011330010231 is 1320100331101.
Together with previous prime (1011330010213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011330010231 - 223 = 1011321621623 is a prime.
It is a super-2 number, since 2×10113300102312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011330010237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505665005115 + 505665005116.
It is an arithmetic number, because the mean of its divisors is an integer number (505665005116).
Almost surely, 21011330010231 is an apocalyptic number.
1011330010231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011330010231 is an equidigital number, since it uses as much as digits as its factorization.
1011330010231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1011330010231 its reverse (1320100331101), we get a palindrome (2331430341332).
The spelling of 1011330010231 in words is "one trillion, eleven billion, three hundred thirty million, ten thousand, two hundred thirty-one".
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