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10113301023 = 37481585763
BaseRepresentation
bin10010110101100110…
…01011101000011111
3222002210221220220120
421122303023220133
5131203001113043
64351311050023
7505421432430
oct113263135037
928083856816
1010113301023
11431a770821
121b62b10913
13c5230a1b7
146bd217487
153e2cdd983
hex25accba1f

10113301023 has 8 divisors (see below), whose sum is σ = 15410744448. Its totient is φ = 5779029144.

The previous prime is 10113300991. The next prime is 10113301061. The reversal of 10113301023 is 32010331101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10113301023 - 25 = 10113300991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10113300993 and 10113301011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113301073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 240792861 + ... + 240792902.

It is an arithmetic number, because the mean of its divisors is an integer number (1926343056).

Almost surely, 210113301023 is an apocalyptic number.

10113301023 is a deficient number, since it is larger than the sum of its proper divisors (5297443425).

10113301023 is an equidigital number, since it uses as much as digits as its factorization.

10113301023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 481585773.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10113301023 its reverse (32010331101), we get a palindrome (42123632124).

The spelling of 10113301023 in words is "ten billion, one hundred thirteen million, three hundred one thousand, twenty-three".

Divisors: 1 3 7 21 481585763 1444757289 3371100341 10113301023