10113311321 has 4 divisors (see below), whose sum is σ = 10241328000. Its totient is φ = 9985294644.

The previous prime is 10113311309. The next prime is 10113311323. The reversal of 10113311321 is 12311331101.

10113311321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113311321 - 2¹⁴ = 10113294937 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 10113311321.

It is not an unprimeable number, because it can be changed into a prime (10113311323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64008221 + ... + 64008378.

It is an arithmetic number, because the mean of its divisors is an integer number (2560332000).

Almost surely, 2^10113311321 is an apocalyptic number.

It is an amenable number.

10113311321 is a deficient number, since it is larger than the sum of its proper divisors (128016679).

10113311321 is an equidigital number, since it uses as much as digits as its factorization.

10113311321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128016678.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10113311321 its reverse (12311331101), we get a palindrome (22424642422).

The spelling of 10113311321 in words is "ten billion, one hundred thirteen million, three hundred eleven thousand, three hundred twenty-one".