1011341200330 has 32 divisors (see below), whose sum is σ = 1823864480640. Its totient is φ = 403770144960.

The previous prime is 1011341200307. The next prime is 1011341200367. The reversal of 1011341200330 is 330021431101.

1011341200330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1011341200330² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011341200298 and 1011341200307.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21853656 + ... + 21899884.

It is an arithmetic number, because the mean of its divisors is an integer number (56995765020).

Almost surely, 2^{1011341200330} is an apocalyptic number.

1011341200330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1011341200330 is a deficient number, since it is larger than the sum of its proper divisors (812523280310).

1011341200330 is a wasteful number, since it uses less digits than its factorization.

1011341200330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50334.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1011341200330 its reverse (330021431101), we get a palindrome (1341362631431).

The spelling of 1011341200330 in words is "one trillion, eleven billion, three hundred forty-one million, two hundred thousand, three hundred thirty".