1011341200367 has 2 divisors, whose sum is σ = 1011341200368. Its totient is φ = 1011341200366.

The previous prime is 1011341200307. The next prime is 1011341200379. The reversal of 1011341200367 is 7630021431101.

It is a strong prime.

It is an emirp because it is prime and its reverse (7630021431101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011341200367 is a prime.

It is a super-2 number, since 2×1011341200367² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011341200307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505670600183 + 505670600184.

It is an arithmetic number, because the mean of its divisors is an integer number (505670600184).

Almost surely, 2^{1011341200367} is an apocalyptic number.

1011341200367 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011341200367 is an equidigital number, since it uses as much as digits as its factorization.

1011341200367 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 29.

Adding to 1011341200367 its reverse (7630021431101), we get a palindrome (8641362631468).

The spelling of 1011341200367 in words is "one trillion, eleven billion, three hundred forty-one million, two hundred thousand, three hundred sixty-seven".