Base | Representation |
---|---|
bin | 11101011011110001010… |
… | …11101101110101110001 |
3 | 10120200110011110202222122 |
4 | 32231320223231311301 |
5 | 113032212030243213 |
6 | 2052334253444025 |
7 | 133031666335214 |
oct | 16557053556561 |
9 | 3520404422878 |
10 | 1011342040433 |
11 | 35a9a924182a |
12 | 1440084a0615 |
13 | 744a502047a |
14 | 36d4091177b |
15 | 1b49236ad08 |
hex | eb78aedd71 |
1011342040433 has 2 divisors, whose sum is σ = 1011342040434. Its totient is φ = 1011342040432.
The previous prime is 1011342040421. The next prime is 1011342040439. The reversal of 1011342040433 is 3340402431101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 809150622784 + 202191417649 = 899528^2 + 449657^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011342040433 - 212 = 1011342036337 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011342040439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505671020216 + 505671020217.
It is an arithmetic number, because the mean of its divisors is an integer number (505671020217).
Almost surely, 21011342040433 is an apocalyptic number.
It is an amenable number.
1011342040433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011342040433 is an equidigital number, since it uses as much as digits as its factorization.
1011342040433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 1011342040433 its reverse (3340402431101), we get a palindrome (4351744471534).
The spelling of 1011342040433 in words is "one trillion, eleven billion, three hundred forty-two million, forty thousand, four hundred thirty-three".
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