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101134433 is a prime number
BaseRepresentation
bin1100000011100…
…11000001100001
321001022011100202
412001303001201
5201342300213
614011354545
72335425401
oct601630141
9231264322
10101134433
11520a6884
1229a52a55
1317c4cc7a
14d608801
158d2ab58
hex6073061

101134433 has 2 divisors, whose sum is σ = 101134434. Its totient is φ = 101134432.

The previous prime is 101134399. The next prime is 101134447. The reversal of 101134433 is 334431101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100661089 + 473344 = 10033^2 + 688^2 .

It is an emirp because it is prime and its reverse (334431101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101134433 - 214 = 101118049 is a prime.

It is not a weakly prime, because it can be changed into another prime (101134483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50567216 + 50567217.

It is an arithmetic number, because the mean of its divisors is an integer number (50567217).

Almost surely, 2101134433 is an apocalyptic number.

It is an amenable number.

101134433 is a deficient number, since it is larger than the sum of its proper divisors (1).

101134433 is an equidigital number, since it uses as much as digits as its factorization.

101134433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 101134433 is about 10056.5616887682. The cubic root of 101134433 is about 465.9074782392.

Adding to 101134433 its reverse (334431101), we get a palindrome (435565534).

The spelling of 101134433 in words is "one hundred one million, one hundred thirty-four thousand, four hundred thirty-three".