Base | Representation |
---|---|
bin | 1100000011100… |
… | …11000010010011 |
3 | 21001022011102121 |
4 | 12001303002103 |
5 | 201342300413 |
6 | 14011355111 |
7 | 2335425502 |
oct | 601630223 |
9 | 231264377 |
10 | 101134483 |
11 | 520a691a |
12 | 29a52a97 |
13 | 17c4ccb8 |
14 | d608839 |
15 | 8d2ab8d |
hex | 6073093 |
101134483 has 2 divisors, whose sum is σ = 101134484. Its totient is φ = 101134482.
The previous prime is 101134447. The next prime is 101134487. The reversal of 101134483 is 384431101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101134483 is a prime.
It is not a weakly prime, because it can be changed into another prime (101134487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50567241 + 50567242.
It is an arithmetic number, because the mean of its divisors is an integer number (50567242).
Almost surely, 2101134483 is an apocalyptic number.
101134483 is a deficient number, since it is larger than the sum of its proper divisors (1).
101134483 is an equidigital number, since it uses as much as digits as its factorization.
101134483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
The square root of 101134483 is about 10056.5641747070. The cubic root of 101134483 is about 465.9075550194.
Adding to 101134483 its reverse (384431101), we get a palindrome (485565584).
The spelling of 101134483 in words is "one hundred one million, one hundred thirty-four thousand, four hundred eighty-three".
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