101140022013 has 4 divisors (see below), whose sum is σ = 134853362688. Its totient is φ = 67426681340.

The previous prime is 101140021993. The next prime is 101140022021. The reversal of 101140022013 is 310220041101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101140022013 - 2¹² = 101140017917 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101140021983 and 101140022001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101140022213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16856670333 + ... + 16856670338.

It is an arithmetic number, because the mean of its divisors is an integer number (33713340672).

Almost surely, 2^101140022013 is an apocalyptic number.

It is an amenable number.

101140022013 is a deficient number, since it is larger than the sum of its proper divisors (33713340675).

101140022013 is an equidigital number, since it uses as much as digits as its factorization.

101140022013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33713340674.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 101140022013 its reverse (310220041101), we get a palindrome (411360063114).

The spelling of 101140022013 in words is "one hundred one billion, one hundred forty million, twenty-two thousand, thirteen".