Base | Representation |
---|---|
bin | 11101011011111001101… |
… | …10110011000110000011 |
3 | 10120200122001012212002122 |
4 | 32231330312303012003 |
5 | 113032332441220103 |
6 | 2052345234234455 |
7 | 133033506420452 |
oct | 16557466630603 |
9 | 3520561185078 |
10 | 1011412054403 |
11 | 35aa34812313 |
12 | 144027a25a2b |
13 | 744b669545a |
14 | 36d49d38b99 |
15 | 1b49859ab38 |
hex | eb7cdb3183 |
1011412054403 has 2 divisors, whose sum is σ = 1011412054404. Its totient is φ = 1011412054402.
The previous prime is 1011412054379. The next prime is 1011412054409. The reversal of 1011412054403 is 3044502141101.
It is a strong prime.
It is an emirp because it is prime and its reverse (3044502141101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1011412054403 - 232 = 1007117087107 is a prime.
It is not a weakly prime, because it can be changed into another prime (1011412054409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505706027201 + 505706027202.
It is an arithmetic number, because the mean of its divisors is an integer number (505706027202).
Almost surely, 21011412054403 is an apocalyptic number.
1011412054403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011412054403 is an equidigital number, since it uses as much as digits as its factorization.
1011412054403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1920, while the sum is 26.
Adding to 1011412054403 its reverse (3044502141101), we get a palindrome (4055914195504).
The spelling of 1011412054403 in words is "one trillion, eleven billion, four hundred twelve million, fifty-four thousand, four hundred three".
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